3/x-2+4/x+3=7/x^2-x-6

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Solution for 3/x-2+4/x+3=7/x^2-x-6 equation: 



3/x-2+4/x+3=7/x^2-x-6

We move all terms to the left:

3/x-2+4/x+3-(7/x^2-x-6)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2-x-6)!=0

x∈R



We add all the numbers together, and all the variables

3/x+4/x-(7/x^2-x-6)+1=0

We get rid of parentheses

3/x+4/x-7/x^2+x+6+1=0

We calculate fractions

We do not support expression: x^3

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